Question-78

probability
counting

A family has six children, three boys and three girls. Assuming all birth orders are equally likely, what is the probability that the three eldest children are girls?

0.05

Label the boys \(B_1, B_2, B_3\) and the girls \(G_1, G_2, G_3\). Since all orders are equally likely, we have:

\[ \cfrac{3! \times 3!}{6!} = \cfrac{1}{20} \]