Question-83

system of equations
matrix
determinant

Choose the correct options from the following:

Option-1

If \(\displaystyle AB=0\), then \(\displaystyle |AB|=0\). This implies that \(\displaystyle |A|\cdot |B|=0\), so the determinant of at least one of these two matrices has to be zero.

Option-2

We have:

\[ \begin{equation*} \begin{aligned} |A| & =|\alpha I|\\ & =\alpha ^{n} \end{aligned} \end{equation*} \]

The determinant of \(\displaystyle A\) will be positive for any arbitrary $$ only if \(\displaystyle n\) is even.

Option-3

Here is a counter example. \(\displaystyle A=\begin{bmatrix} 0 & 1\\ 1 & 0 \end{bmatrix}\). \(\displaystyle |A|=-1\).

Option-4

If \(\displaystyle Ax=0\) has a unique solution for some square matrix \(\displaystyle A\), the columns of \(\displaystyle A\) are linearly independent and hence \(\displaystyle |A|\neq 0\).